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Why equations lose marks
A balanced equation has the same number of each type of atom on both sides. Atoms are rearranged in a reaction, never created or destroyed, so the count must match.
The 0620 syllabus asks you to write word and symbol equations with state symbols. Extended candidates must also write ionic equations and work out an equation from information in the question.
Three mistakes cost the most marks. The formulae are wrong before balancing starts. The equation is balanced by changing a subscript. Or the state symbols are missing or guessed.
The five-step method
Work through these steps in order, every time.
Write the correct formulae
Turn the word equation into formulae. Use ion charges for ionic compounds: Al3+ and Cl− give AlCl3. Remember the diatomic elements.
Tip. Once a formula is written, treat it as locked. You will only ever add numbers in front of it.Count the atoms on each side
Make a quick tally under the equation, one column per element. A coefficient multiplies everything in the formula after it, so 2H2O contains 4 H and 2 O.
Balance one element at a time
Pick an element that appears in only one substance on each side. Add a coefficient so its count matches. If the counts are 2 and 3, aim for 6, the lowest common multiple.
Save lone elements for last
Elements that appear on their own, such as O2, H2 or a metal, are the easiest to adjust. Changing them disturbs nothing else, so balance them at the end.
Tip. If you need half a molecule, such as 3½ O2, double every coefficient to clear the fraction.Recount, then add state symbols
Check every element again on both sides. Then add (s), (l), (g) or (aq) after each formula, using the information in the question.
Tip. A coefficient of 1 is not written. Make sure the coefficients cannot all be divided by a common number.
For a fuel burning in oxygen, a useful order is carbon, then hydrogen, then oxygen. Propane gives C3H8 + 5O2 → 3CO2 + 4H2O. Ethane needs 3½ O2 at first, so double it: 2C2H6 + 7O2 → 4CO2 + 6H2O.
Extended: ionic equations. These show only the ions that change. Atoms and total charge must both balance. Mixing silver nitrate and sodium chloride solutions gives Ag+(aq) + Cl−(aq) → AgCl(s). Charge is 0 on each side. The neutralisation of an acid by an alkali is H+(aq) + OH−(aq) → H2O(l).
Barium chloride and sodium sulfate solutions form a white precipitate in the same way: Ba2+(aq) + SO42−(aq) → BaSO4(s). The charges are 2+ and 2−, so the total is 0 on both sides.
Worked example
This question gives a reaction in words. You must write the formulae, balance them and add state symbols.
Aluminium reacts with dilute hydrochloric acid. The products are aluminium chloride solution and hydrogen gas. Write the balanced symbol equation for this reaction, including state symbols.
2Al + 6HCl → 2AlCl3 + 3H2
Look at the second line. Fixing hydrogen changed chlorine, so chlorine had to be fixed again. That back-and-forth is normal. Keep going until a full recount comes out equal.
Sodium reacts with water to form sodium hydroxide solution and hydrogen gas. Write the balanced symbol equation, including state symbols.
Show the answer
H is 2 on the left and 3 on the right, so try 2H2O and 2NaOH. Then Na needs 2Na.
Check: 2 Na, 4 H, 2 O on each side.
2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)